I've been reading up on load sensors and the sparkfun ADC tutorial, to understand this. Like others here, I'm working on an arduino based data-logging scale. For my application I ended up gluing a nut right onto the little round nib and then screwing a bolt into it, but there are definitely other (better) ways depending on your application. Then a balanced force applied uniformly across the board or directly in the middle would lead to no voltage change, while an uneven force distribution across the board would lead to either a positive or negative voltage change depending on the side.Īs for the actual mechanical application of the force to the sensor, you might have to get a little creative. For example, you could have a board or something supported on each end by the two sensors. Now I can think of some situations where you might use this behavior. Pushing equally on both at the same time will give you nothing because you're keeping the bridge balanced. If you have the circuit wired you can see that pushing on one sensor will result in a positive Vout while pushing on the other will result in a negative Vout. And actually, because of the nature of a Wheatstone bridge and the fact that the two sensors behave the same way, applying a load to BOTH sensors would completely cancel out the signal. The other is just there to balance the Wheatstone bridge. As for sensing, just use ONE of the sensors. I just wrote out a (lengthy) response to Gizmoguy explaining things in more detail, so you might want to check that out, but it sounds like you get the circuitry. I will try to get the exact given temperature. I'll try to get a Ampop to amplify the signal through the red wires and do some tests, what I get is, according to the scheme of the Wheatstone bridge that says to calculate an unknown resistance is needed to know the value of the other three is attempting to use a single sensor but doubt is the temperature compensation, work environment where sensors will suffer sudden temperature changes, so will be at 5 ° C in winter to 40 º C in summer. The reading remains at rest 0.1 mV, but pressing either always gives me a positive value. Right now, the two are at rest and the multimeter will mark me 0.6 mV, I suppose it's an error rate of internal resistance. If I press a sensor gives a positive value and if I pull the other gives a negative value. Then I measure the voltage difference between the red wires and increase as the effort mV. A 25% RE-STOCKING FEE WILL APPLY for refund or to purchase another item/s of a brand different from the original purchase.Hi, I recently purchased two sensors and reading the comments I 've gotten them work in the following ways :. ![]()
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